Rank the bond dissociation energies of the bo | vedclass

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(D) The bond dissociation energy is inversely proportional to the stability of the free radical formed after homolytic cleavage of the $C-H$ bond.$1$.

Vedclass · Accepted Answer

$3 < 1 < 2$

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(D) The bond dissociation energy is inversely proportional to the stability of the free radical formed after homolytic cleavage of the $C-H$ bond.$1$. Bond $3$ leads to a tertiary $(3^{\circ})$ radical on the cyclohexane ring,which is the most stable due to hyperconjugation and inductive effects.$2$. Bond $1$ leads to a secondary $(2^{\circ})$ radical on the cyclohexane ring,which is less stable than the $3^{\circ}$ radical.$3$. Bond $2$ leads to a primary $(1^{\circ})$ radical on the methyl group,which is the least stable.Since the stability of radicals is $3^{\circ} > 2^{\circ} > 1^{\circ}$,the bond dissociation energy order is $3 < 1 < 2$.

Rank the bond dissociation energies of the bonds indicated with the arrows (from smallest to largest).

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